lim x → 5 x 2 – 6 x – 16 x 2 + x – 72
Step 1: Try Option 1: Plug it in
Always try plugging in the x – value you are heading towards.
lim x → 5 x 2 – 6 x – 16 x 2 + x – 72 = (5) 2 – 6 (5) – 16 (5) 2 + (5) – 72 = 1 2
Final Result:
lim x → 5 x 2 – 6 x – 16 x 2 + x – 72 = 1 2
Meaning: The overall limit as x approaches 5 of x 2 – 6 x – 16 x 2 + x – 72 is y = 1 2 .
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